'Weak Dependency Graph [60.0]'
------------------------------
Answer:           YES(?,O(n^1))
Input Problem:    innermost runtime-complexity with respect to
  Rules:
    {  f(a, empty()) -> g(a, empty())
     , f(a, cons(x, k)) -> f(cons(x, a), k)
     , g(empty(), d) -> d
     , g(cons(x, k), d) -> g(k, cons(x, d))}

Details:         
  We have computed the following set of weak (innermost) dependency pairs:
   {  f^#(a, empty()) -> c_0(g^#(a, empty()))
    , f^#(a, cons(x, k)) -> c_1(f^#(cons(x, a), k))
    , g^#(empty(), d) -> c_2()
    , g^#(cons(x, k), d) -> c_3(g^#(k, cons(x, d)))}
  
  The usable rules are:
   {}
  
  The estimated dependency graph contains the following edges:
   {f^#(a, empty()) -> c_0(g^#(a, empty()))}
     ==> {g^#(cons(x, k), d) -> c_3(g^#(k, cons(x, d)))}
   {f^#(a, empty()) -> c_0(g^#(a, empty()))}
     ==> {g^#(empty(), d) -> c_2()}
   {f^#(a, cons(x, k)) -> c_1(f^#(cons(x, a), k))}
     ==> {f^#(a, cons(x, k)) -> c_1(f^#(cons(x, a), k))}
   {f^#(a, cons(x, k)) -> c_1(f^#(cons(x, a), k))}
     ==> {f^#(a, empty()) -> c_0(g^#(a, empty()))}
   {g^#(cons(x, k), d) -> c_3(g^#(k, cons(x, d)))}
     ==> {g^#(cons(x, k), d) -> c_3(g^#(k, cons(x, d)))}
   {g^#(cons(x, k), d) -> c_3(g^#(k, cons(x, d)))}
     ==> {g^#(empty(), d) -> c_2()}
  
  We consider the following path(s):
   1) {  f^#(a, cons(x, k)) -> c_1(f^#(cons(x, a), k))
       , f^#(a, empty()) -> c_0(g^#(a, empty()))
       , g^#(cons(x, k), d) -> c_3(g^#(k, cons(x, d)))}
      
      The usable rules for this path are empty.
      
        We have oriented the usable rules with the following strongly linear interpretation:
          Interpretation Functions:
           f(x1, x2) = [0] x1 + [0] x2 + [0]
           empty() = [0]
           g(x1, x2) = [0] x1 + [0] x2 + [0]
           cons(x1, x2) = [0] x1 + [0] x2 + [0]
           f^#(x1, x2) = [0] x1 + [0] x2 + [0]
           c_0(x1) = [0] x1 + [0]
           g^#(x1, x2) = [0] x1 + [0] x2 + [0]
           c_1(x1) = [0] x1 + [0]
           c_2() = [0]
           c_3(x1) = [0] x1 + [0]
        
        We have applied the subprocessor on the resulting DP-problem:
        
          'Weight Gap Principle'
          ----------------------
          Answer:           YES(?,O(n^1))
          Input Problem:    innermost DP runtime-complexity with respect to
            Strict Rules: {g^#(cons(x, k), d) -> c_3(g^#(k, cons(x, d)))}
            Weak Rules:
              {  f^#(a, empty()) -> c_0(g^#(a, empty()))
               , f^#(a, cons(x, k)) -> c_1(f^#(cons(x, a), k))}
          
          Details:         
            'fastest of 'combine', 'Bounds with default enrichment', 'Bounds with default enrichment''
            ------------------------------------------------------------------------------------------
            Answer:           YES(?,O(n^1))
            Input Problem:    innermost DP runtime-complexity with respect to
              Strict Rules: {g^#(cons(x, k), d) -> c_3(g^#(k, cons(x, d)))}
              Weak Rules:
                {  f^#(a, empty()) -> c_0(g^#(a, empty()))
                 , f^#(a, cons(x, k)) -> c_1(f^#(cons(x, a), k))}
            
            Details:         
              The problem was solved by processor 'combine':
              'combine'
              ---------
              Answer:           YES(?,O(n^1))
              Input Problem:    innermost DP runtime-complexity with respect to
                Strict Rules: {g^#(cons(x, k), d) -> c_3(g^#(k, cons(x, d)))}
                Weak Rules:
                  {  f^#(a, empty()) -> c_0(g^#(a, empty()))
                   , f^#(a, cons(x, k)) -> c_1(f^#(cons(x, a), k))}
              
              Details:         
                'sequentially if-then-else, sequentially'
                -----------------------------------------
                Answer:           YES(?,O(n^1))
                Input Problem:    innermost DP runtime-complexity with respect to
                  Strict Rules: {g^#(cons(x, k), d) -> c_3(g^#(k, cons(x, d)))}
                  Weak Rules:
                    {  f^#(a, empty()) -> c_0(g^#(a, empty()))
                     , f^#(a, cons(x, k)) -> c_1(f^#(cons(x, a), k))}
                
                Details:         
                  'if Check whether the TRS is strict trs contains single rule then fastest else fastest'
                  ---------------------------------------------------------------------------------------
                  Answer:           YES(?,O(n^1))
                  Input Problem:    innermost DP runtime-complexity with respect to
                    Strict Rules: {g^#(cons(x, k), d) -> c_3(g^#(k, cons(x, d)))}
                    Weak Rules:
                      {  f^#(a, empty()) -> c_0(g^#(a, empty()))
                       , f^#(a, cons(x, k)) -> c_1(f^#(cons(x, a), k))}
                  
                  Details:         
                    a) We first check the conditional [Success]:
                       We are considering a strict trs contains single rule TRS.
                    
                    b) We continue with the then-branch:
                       The problem was solved by processor 'fastest of 'Matrix Interpretation', 'Matrix Interpretation', 'Matrix Interpretation'':
                       'fastest of 'Matrix Interpretation', 'Matrix Interpretation', 'Matrix Interpretation''
                       --------------------------------------------------------------------------------------
                       Answer:           YES(?,O(n^1))
                       Input Problem:    innermost DP runtime-complexity with respect to
                         Strict Rules: {g^#(cons(x, k), d) -> c_3(g^#(k, cons(x, d)))}
                         Weak Rules:
                           {  f^#(a, empty()) -> c_0(g^#(a, empty()))
                            , f^#(a, cons(x, k)) -> c_1(f^#(cons(x, a), k))}
                       
                       Details:         
                         The problem was solved by processor 'Matrix Interpretation':
                         'Matrix Interpretation'
                         -----------------------
                         Answer:           YES(?,O(n^1))
                         Input Problem:    innermost DP runtime-complexity with respect to
                           Strict Rules: {g^#(cons(x, k), d) -> c_3(g^#(k, cons(x, d)))}
                           Weak Rules:
                             {  f^#(a, empty()) -> c_0(g^#(a, empty()))
                              , f^#(a, cons(x, k)) -> c_1(f^#(cons(x, a), k))}
                         
                         Details:         
                           Interpretation Functions:
                            f(x1, x2) = [0] x1 + [0] x2 + [0]
                            empty() = [4]
                            g(x1, x2) = [0] x1 + [0] x2 + [0]
                            cons(x1, x2) = [1] x1 + [1] x2 + [3]
                            f^#(x1, x2) = [7] x1 + [7] x2 + [0]
                            c_0(x1) = [1] x1 + [6]
                            g^#(x1, x2) = [4] x1 + [3] x2 + [7]
                            c_1(x1) = [1] x1 + [0]
                            c_2() = [0]
                            c_3(x1) = [1] x1 + [0]
      
   2) {f^#(a, cons(x, k)) -> c_1(f^#(cons(x, a), k))}
      
      The usable rules for this path are empty.
      
        We have oriented the usable rules with the following strongly linear interpretation:
          Interpretation Functions:
           f(x1, x2) = [0] x1 + [0] x2 + [0]
           empty() = [0]
           g(x1, x2) = [0] x1 + [0] x2 + [0]
           cons(x1, x2) = [0] x1 + [0] x2 + [0]
           f^#(x1, x2) = [0] x1 + [0] x2 + [0]
           c_0(x1) = [0] x1 + [0]
           g^#(x1, x2) = [0] x1 + [0] x2 + [0]
           c_1(x1) = [0] x1 + [0]
           c_2() = [0]
           c_3(x1) = [0] x1 + [0]
        
        We have applied the subprocessor on the resulting DP-problem:
        
          'Weight Gap Principle'
          ----------------------
          Answer:           YES(?,O(n^1))
          Input Problem:    innermost DP runtime-complexity with respect to
            Strict Rules: {f^#(a, cons(x, k)) -> c_1(f^#(cons(x, a), k))}
            Weak Rules: {}
          
          Details:         
            'fastest of 'combine', 'Bounds with default enrichment', 'Bounds with default enrichment''
            ------------------------------------------------------------------------------------------
            Answer:           YES(?,O(n^1))
            Input Problem:    innermost DP runtime-complexity with respect to
              Strict Rules: {f^#(a, cons(x, k)) -> c_1(f^#(cons(x, a), k))}
              Weak Rules: {}
            
            Details:         
              The problem was solved by processor 'combine':
              'combine'
              ---------
              Answer:           YES(?,O(n^1))
              Input Problem:    innermost DP runtime-complexity with respect to
                Strict Rules: {f^#(a, cons(x, k)) -> c_1(f^#(cons(x, a), k))}
                Weak Rules: {}
              
              Details:         
                'sequentially if-then-else, sequentially'
                -----------------------------------------
                Answer:           YES(?,O(n^1))
                Input Problem:    innermost DP runtime-complexity with respect to
                  Strict Rules: {f^#(a, cons(x, k)) -> c_1(f^#(cons(x, a), k))}
                  Weak Rules: {}
                
                Details:         
                  'if Check whether the TRS is strict trs contains single rule then fastest else fastest'
                  ---------------------------------------------------------------------------------------
                  Answer:           YES(?,O(n^1))
                  Input Problem:    innermost DP runtime-complexity with respect to
                    Strict Rules: {f^#(a, cons(x, k)) -> c_1(f^#(cons(x, a), k))}
                    Weak Rules: {}
                  
                  Details:         
                    a) We first check the conditional [Success]:
                       We are considering a strict trs contains single rule TRS.
                    
                    b) We continue with the then-branch:
                       The problem was solved by processor 'fastest of 'Matrix Interpretation', 'Matrix Interpretation', 'Matrix Interpretation'':
                       'fastest of 'Matrix Interpretation', 'Matrix Interpretation', 'Matrix Interpretation''
                       --------------------------------------------------------------------------------------
                       Answer:           YES(?,O(n^1))
                       Input Problem:    innermost DP runtime-complexity with respect to
                         Strict Rules: {f^#(a, cons(x, k)) -> c_1(f^#(cons(x, a), k))}
                         Weak Rules: {}
                       
                       Details:         
                         The problem was solved by processor 'Matrix Interpretation':
                         'Matrix Interpretation'
                         -----------------------
                         Answer:           YES(?,O(n^1))
                         Input Problem:    innermost DP runtime-complexity with respect to
                           Strict Rules: {f^#(a, cons(x, k)) -> c_1(f^#(cons(x, a), k))}
                           Weak Rules: {}
                         
                         Details:         
                           Interpretation Functions:
                            f(x1, x2) = [0] x1 + [0] x2 + [0]
                            empty() = [0]
                            g(x1, x2) = [0] x1 + [0] x2 + [0]
                            cons(x1, x2) = [1] x1 + [1] x2 + [5]
                            f^#(x1, x2) = [1] x1 + [2] x2 + [3]
                            c_0(x1) = [0] x1 + [0]
                            g^#(x1, x2) = [0] x1 + [0] x2 + [0]
                            c_1(x1) = [1] x1 + [0]
                            c_2() = [0]
                            c_3(x1) = [0] x1 + [0]
      
   3) {  f^#(a, cons(x, k)) -> c_1(f^#(cons(x, a), k))
       , f^#(a, empty()) -> c_0(g^#(a, empty()))
       , g^#(cons(x, k), d) -> c_3(g^#(k, cons(x, d)))
       , g^#(empty(), d) -> c_2()}
      
      The usable rules for this path are empty.
      
        We have oriented the usable rules with the following strongly linear interpretation:
          Interpretation Functions:
           f(x1, x2) = [0] x1 + [0] x2 + [0]
           empty() = [0]
           g(x1, x2) = [0] x1 + [0] x2 + [0]
           cons(x1, x2) = [0] x1 + [0] x2 + [0]
           f^#(x1, x2) = [0] x1 + [0] x2 + [0]
           c_0(x1) = [0] x1 + [0]
           g^#(x1, x2) = [0] x1 + [0] x2 + [0]
           c_1(x1) = [0] x1 + [0]
           c_2() = [0]
           c_3(x1) = [0] x1 + [0]
        
        We have applied the subprocessor on the resulting DP-problem:
        
          'Weight Gap Principle'
          ----------------------
          Answer:           YES(?,O(n^1))
          Input Problem:    innermost DP runtime-complexity with respect to
            Strict Rules: {g^#(empty(), d) -> c_2()}
            Weak Rules:
              {  g^#(cons(x, k), d) -> c_3(g^#(k, cons(x, d)))
               , f^#(a, empty()) -> c_0(g^#(a, empty()))
               , f^#(a, cons(x, k)) -> c_1(f^#(cons(x, a), k))}
          
          Details:         
            We apply the weight gap principle, strictly orienting the rules
            {g^#(empty(), d) -> c_2()}
            and weakly orienting the rules
            {  g^#(cons(x, k), d) -> c_3(g^#(k, cons(x, d)))
             , f^#(a, empty()) -> c_0(g^#(a, empty()))
             , f^#(a, cons(x, k)) -> c_1(f^#(cons(x, a), k))}
            using the following strongly linear interpretation:
              Processor 'Matrix Interpretation' oriented the following rules strictly:
              
              {g^#(empty(), d) -> c_2()}
              
              Details:
                 Interpretation Functions:
                  f(x1, x2) = [0] x1 + [0] x2 + [0]
                  empty() = [0]
                  g(x1, x2) = [0] x1 + [0] x2 + [0]
                  cons(x1, x2) = [1] x1 + [1] x2 + [0]
                  f^#(x1, x2) = [1] x1 + [1] x2 + [1]
                  c_0(x1) = [1] x1 + [0]
                  g^#(x1, x2) = [1] x1 + [1] x2 + [1]
                  c_1(x1) = [1] x1 + [0]
                  c_2() = [0]
                  c_3(x1) = [1] x1 + [0]
              
            Finally we apply the subprocessor
            'Empty TRS'
            -----------
            Answer:           YES(?,O(1))
            Input Problem:    innermost DP runtime-complexity with respect to
              Strict Rules: {}
              Weak Rules:
                {  g^#(empty(), d) -> c_2()
                 , g^#(cons(x, k), d) -> c_3(g^#(k, cons(x, d)))
                 , f^#(a, empty()) -> c_0(g^#(a, empty()))
                 , f^#(a, cons(x, k)) -> c_1(f^#(cons(x, a), k))}
            
            Details:         
              The given problem does not contain any strict rules
      
   4) {  f^#(a, cons(x, k)) -> c_1(f^#(cons(x, a), k))
       , f^#(a, empty()) -> c_0(g^#(a, empty()))
       , g^#(empty(), d) -> c_2()}
      
      The usable rules for this path are empty.
      
        We have oriented the usable rules with the following strongly linear interpretation:
          Interpretation Functions:
           f(x1, x2) = [0] x1 + [0] x2 + [0]
           empty() = [0]
           g(x1, x2) = [0] x1 + [0] x2 + [0]
           cons(x1, x2) = [0] x1 + [0] x2 + [0]
           f^#(x1, x2) = [0] x1 + [0] x2 + [0]
           c_0(x1) = [0] x1 + [0]
           g^#(x1, x2) = [0] x1 + [0] x2 + [0]
           c_1(x1) = [0] x1 + [0]
           c_2() = [0]
           c_3(x1) = [0] x1 + [0]
        
        We have applied the subprocessor on the resulting DP-problem:
        
          'Weight Gap Principle'
          ----------------------
          Answer:           YES(?,O(n^1))
          Input Problem:    innermost DP runtime-complexity with respect to
            Strict Rules: {g^#(empty(), d) -> c_2()}
            Weak Rules:
              {  f^#(a, empty()) -> c_0(g^#(a, empty()))
               , f^#(a, cons(x, k)) -> c_1(f^#(cons(x, a), k))}
          
          Details:         
            We apply the weight gap principle, strictly orienting the rules
            {g^#(empty(), d) -> c_2()}
            and weakly orienting the rules
            {  f^#(a, empty()) -> c_0(g^#(a, empty()))
             , f^#(a, cons(x, k)) -> c_1(f^#(cons(x, a), k))}
            using the following strongly linear interpretation:
              Processor 'Matrix Interpretation' oriented the following rules strictly:
              
              {g^#(empty(), d) -> c_2()}
              
              Details:
                 Interpretation Functions:
                  f(x1, x2) = [0] x1 + [0] x2 + [0]
                  empty() = [0]
                  g(x1, x2) = [0] x1 + [0] x2 + [0]
                  cons(x1, x2) = [1] x1 + [1] x2 + [0]
                  f^#(x1, x2) = [1] x1 + [1] x2 + [1]
                  c_0(x1) = [1] x1 + [0]
                  g^#(x1, x2) = [1] x1 + [1] x2 + [1]
                  c_1(x1) = [1] x1 + [0]
                  c_2() = [0]
                  c_3(x1) = [0] x1 + [0]
              
            Finally we apply the subprocessor
            'Empty TRS'
            -----------
            Answer:           YES(?,O(1))
            Input Problem:    innermost DP runtime-complexity with respect to
              Strict Rules: {}
              Weak Rules:
                {  g^#(empty(), d) -> c_2()
                 , f^#(a, empty()) -> c_0(g^#(a, empty()))
                 , f^#(a, cons(x, k)) -> c_1(f^#(cons(x, a), k))}
            
            Details:         
              The given problem does not contain any strict rules
      
   5) {  f^#(a, cons(x, k)) -> c_1(f^#(cons(x, a), k))
       , f^#(a, empty()) -> c_0(g^#(a, empty()))}
      
      The usable rules for this path are empty.
      
        We have oriented the usable rules with the following strongly linear interpretation:
          Interpretation Functions:
           f(x1, x2) = [0] x1 + [0] x2 + [0]
           empty() = [0]
           g(x1, x2) = [0] x1 + [0] x2 + [0]
           cons(x1, x2) = [0] x1 + [0] x2 + [0]
           f^#(x1, x2) = [0] x1 + [0] x2 + [0]
           c_0(x1) = [0] x1 + [0]
           g^#(x1, x2) = [0] x1 + [0] x2 + [0]
           c_1(x1) = [0] x1 + [0]
           c_2() = [0]
           c_3(x1) = [0] x1 + [0]
        
        We have applied the subprocessor on the resulting DP-problem:
        
          'Weight Gap Principle'
          ----------------------
          Answer:           YES(?,O(n^1))
          Input Problem:    innermost DP runtime-complexity with respect to
            Strict Rules: {f^#(a, empty()) -> c_0(g^#(a, empty()))}
            Weak Rules: {f^#(a, cons(x, k)) -> c_1(f^#(cons(x, a), k))}
          
          Details:         
            We apply the weight gap principle, strictly orienting the rules
            {f^#(a, empty()) -> c_0(g^#(a, empty()))}
            and weakly orienting the rules
            {f^#(a, cons(x, k)) -> c_1(f^#(cons(x, a), k))}
            using the following strongly linear interpretation:
              Processor 'Matrix Interpretation' oriented the following rules strictly:
              
              {f^#(a, empty()) -> c_0(g^#(a, empty()))}
              
              Details:
                 Interpretation Functions:
                  f(x1, x2) = [0] x1 + [0] x2 + [0]
                  empty() = [0]
                  g(x1, x2) = [0] x1 + [0] x2 + [0]
                  cons(x1, x2) = [1] x1 + [1] x2 + [0]
                  f^#(x1, x2) = [1] x1 + [1] x2 + [1]
                  c_0(x1) = [1] x1 + [0]
                  g^#(x1, x2) = [1] x1 + [1] x2 + [0]
                  c_1(x1) = [1] x1 + [0]
                  c_2() = [0]
                  c_3(x1) = [0] x1 + [0]
              
            Finally we apply the subprocessor
            'Empty TRS'
            -----------
            Answer:           YES(?,O(1))
            Input Problem:    innermost DP runtime-complexity with respect to
              Strict Rules: {}
              Weak Rules:
                {  f^#(a, empty()) -> c_0(g^#(a, empty()))
                 , f^#(a, cons(x, k)) -> c_1(f^#(cons(x, a), k))}
            
            Details:         
              The given problem does not contain any strict rules